X^2+3x+0.2=0

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Solution for X^2+3x+0.2=0 equation: 



X^2+3X+0.2=0

a = 1; b = 3; c = +0.2;
Δ = b2-4ac
Δ = 32-4·1·0.2
Δ = 8.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{8.2}}{2*1}=\frac{-3-\sqrt{8.2}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{8.2}}{2*1}=\frac{-3+\sqrt{8.2}}{2}
$

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